HSC Maths Complex Numbers: The Ext 2 Survival Guide

Last updated: 24 July 2026

Complex numbers are the first thing you learn in Extension 2 and they never leave. They turn up in polynomials, vectors, calculus, proofs. If you nail them early, the rest of Ext 2 slots into place.

The big idea

A complex number has a real part and an imaginary part: z=x+iyz = x + iy, where i2=1i^2 = -1.

That ii is the whole trick. Every complex number is a point on the Argand diagram — x-axis is real, y-axis is imaginary.

Modulus and argument

The modulus (z|z|) is the distance from the origin — Pythagoras again. The argument (textargz\\text{arg } z) is the angle from the positive real axis.

z=sqrtx2+y2|z| = \\sqrt{x^2 + y^2} textargz=tan1(y/x)\\text{arg } z = \\tan^{-1}(y/x)

These two things let you switch between Cartesian (x+iyx + iy) and modulus-argument (polar) form. The polar form is:

z=r(costheta+isintheta)z = r(\\cos\\theta + i\\sin\\theta)

where r=zr = |z| and theta=textargz\\theta = \\text{arg } z.

Why polar form matters

Multiplying and dividing complex numbers is tedious in Cartesian. In polar form it's clean:

That last one is De Moivre's theorem:

(costheta+isintheta)n=cos(ntheta)+isin(ntheta)(\\cos\\theta + i\\sin\\theta)^n = \\cos(n\\theta) + i\\sin(n\\theta)

De Moivre's theorem — the workhorse

This theorem is how you find powers of complex numbers, roots of complex numbers, and trig identities.

Finding roots: To find the nnth roots of a complex number, raise the modulus to 1/n1/n and divide the argument by nn. Add 2pi2\\pi for each successive root. The roots are equally spaced around the Argand circle.

Trig identities: Expand (costheta+isintheta)n(\\cos\\theta + i\\sin\\theta)^n using the binomial theorem, equate real and imaginary parts, and you get cos(ntheta)\\cos(n\\theta) and sin(ntheta)\\sin(n\\theta) expressed in powers of costheta\\cos\\theta and sintheta\\sin\\theta.

Conjugates

The conjugate of x+iyx + iy is xiyx - iy. Visually, it's a reflection across the real axis.

Key facts:

Polynomials with complex roots

If a polynomial has real coefficients and one complex root a+iba + ib, then aiba - ib is also a root. This is why cubics always have at least one real root — the complex ones come in pairs.

You'll use this to factor polynomials that look unfactorable and to find all roots of a quartic when you're given one complex root.

The loci questions

"Sketch the region where z(1+i)<2|z - (1 + i)| < 2" — this is describing a circle centred at (1,1)(1, 1) with radius 2. Loci questions test whether you see geometry in the algebra.

Common ones:

How to get good

Complex numbers snowball. If you're shaky on polar form, De Moivre's will be miserable. Practise the conversions first, then the theorems, then the loci.

Get topic-by-topic complex number practice with instant solutions on PracticePapers.io, free during beta.

Memory aid